![Sam Walters ☕️ on Twitter: "The boundary of closed sets in topological spaces acts like the derivative of #calculus: it has the Leibniz product rule. Indeed, Stokes' Theorem equates the integral of Sam Walters ☕️ on Twitter: "The boundary of closed sets in topological spaces acts like the derivative of #calculus: it has the Leibniz product rule. Indeed, Stokes' Theorem equates the integral of](https://pbs.twimg.com/media/E7DRNj0XIAcTK3J.jpg:large)
Sam Walters ☕️ on Twitter: "The boundary of closed sets in topological spaces acts like the derivative of #calculus: it has the Leibniz product rule. Indeed, Stokes' Theorem equates the integral of
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show that subspace topology and order topology will be same for a non-degenerate set X - Mathematics Stack Exchange
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